Python election challenge

Basically, there is an election on 3 regions where either candidate needs to win 2 in order to win the election. Idea is to simulate 10000 elections to see which candidate wins. I think my solution works but I am not happy with the huge list of if statements and wondering of if there is a better way for this.

# Assignment simulate elections page 257

# 2 Candidates A and B

# Candidate A has following odds:
# 87% change of winning in region 1
# 65% changes of winning in region 2
# 17% changes of winning in region 3

from random import random

candidate_a_won = 0
candidate_b_won = 0

for i in range(0, 10000):
    result = random()
    candidate_a = 0
    candidate_b = 0
    if result + .87 >= 1:
        candidate_a += 1
    else:
        candidate_b += 1
    if result + .65 >= 1:
        candidate_a += 1
    else:
        candidate_b += 1
    if result + .17 >= 1:
        candidate_a += 1
    else:
        candidate_b += 1
    if candidate_a > candidate_b:
        candidate_a_won += 1
    else:
        candidate_b_won += 1

print('Candidate A won elections {} times, candidate B won elections {} times'.format(candidate_a_won, candidate_b_won))

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Your code has a problem. Candidate A can loose region 1, but win region 3.
Where with your code they can only win region 3 if they win region 2 and 1.
This is as they are independent, and so you should random in each check.

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You want to move your chances outside the loop into an array.

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You can simplify your ifs into one comprehension.

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Candidate a wins if they have more than half the regions, you don't need to calculate the amount of regions candidate b wins.

And so you could change your code to the following:

from random import random

AMOUNT = 10000
region_chances = [87, 65, 17]
region_chances = [1 - n / 100 for n in region_chances]
regions = len(region_chances)
candidate_a_won = sum(
    sum(random() >= chance for chance in region_chances) * 2 > regions
    for _ in range(AMOUNT)
)
candidate_b_won = AMOUNT - candidate_a_won
print('Candidate A won elections {} times, candidate B won elections {} times'.format(candidate_a_won, candidate_b_won))

If you want to extend on the above then it'll be hard if you decide to have more than two candidates, or even amounts of states.
But as this is a challenge, I don't think you need to worry about these situations.

StackExchange Code Review Q#154364, answer score: 5