Create the English word for a number

I cobbled together a function from various sources that takes an integer and returns it as its respective English word formatted as a string. The function is as follows:

def int2word(num, separator="-"):
    """Transforms integers = 0:
            words = twenty2ninety[tens] + separator + \
                ones_and_teens[below_ten].lower()
        else:
            words = twenty2ninety[tens]
        return words

    elif 100  0:
                words = ones_and_teens[hundreds] + separator + "hundred" + separator + twenty2ninety[
                    tens].lower() + separator + ones_and_teens[below_ten].lower()
            else:
                words = ones_and_teens[
                    hundreds] + separator + "hundred" + separator + ones_and_teens[below_ten].lower()
        return words

    else:
        print("num out of range")

There's an easier way.

We have the num2words module which can be easily installed via pip:

pip install num2words

The advantage of this module is that it supports multiple languages:

• en (English, default)

• fr (French)

• de (German)

• es (Spanish)

• lt (Lithuanian)

• lv (Latvian)

• en_GB (British English)

• en_IN (Indian English)

• no (Norwegian)

• pl (Polish)

• ru (Russian)

• dk (Danish)

• pt_BR (Brazilian Portuguese)

More, you can even generate ordinal numbers like forty-second.

A small python example for converting numbers to words using num2words looks like this:

>>> from num2words import num2words
>>> num2words(42)
forty-two
>>> num2words(42, ordinal=True)
forty-second

You can read more about what you can do using this module here

NOTE: In case somebody is wondering why this is not a code review (such as comments on the posted code), is because in the unedited question the author specifically asked if there is already a library for this.

StackExchange Code Review Q#156590, answer score: 23